本帖最后由 Sunqh 于 2022-8-24 11:26 编辑 " O/ O. L! X" A6 e) O; W
c0 b! n' [2 `/ `8 x' `我认为林德公司的这一套能耗折算标准基本合理,可以验算一下:
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4 Z! d6 b0 |. }9 ~) m液氧0.85kWh/Nm3,其中分离能耗0.35kWh/Nm3,液化能耗0.50kWh/Nm3
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& t' i e3 R, @* @8 k0 }, W液氮0.85*0.7=0.595kWh/Nm3,其中分离功耗0.05kWh/Nm3,液化能耗0.545kWh/Nm3,氮气最小液化功0.27kWh/Nm3,液化效率大约50%
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: K5 E I7 T1 x23.1bar氧气单耗0.85*0.57=0.485kWh/Nm3,其中分离功耗0.35kWh/Nm3,压缩功耗log(23.1)/10=0.136kWh/Nm3,与0.485-0.35=0.135基本相同5 s& M6 H' B0 k! o, I$ j6 l
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5.1bar氮气单耗0.85*0.12=0.102kWh/Nm3,其中分离功耗0.05kWh/Nm3,压缩功耗log(5.1)/10=0.071kWh/Nm3,与0.102-0.05=0.052接近 |